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ch23_p68 - x = 0 end(with Φ = –(2 π(0.20 2(b By...

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68. (a) There is no flux through the sides, so we have two contributions to the flux, one from the x = 2 end (with Φ 2 = +(2 + 2)( π (0.20) 2 ) = 0.50 N·m 2 /C) and one from the
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Unformatted text preview: x = 0 end (with Φ = –(2)( π (0.20) 2 )). (b) By Gauss’ law we have q enc = ε ( Φ 2 + Φ ) = 2.2 × 10 –12 C....
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