ch23_p80 - 80. We can express Eq. 23-17 in terms of the...

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80. We can express Eq. 23-17 in terms of the charge density ρ as follows: E = q 4 πε o r 2 = ρ 4 3 π R 3 4 πε o r 2 = ρ R 3 3 ε o r 2 . Thus, at r = 2 R , we have (when the ball is solid) E 1 = ρ R 3 3 ε o (2 R ) 2 = ρ 12 ε o R . Now, with the hollow core of radius R /2, we have a similar field but without the contribution from those charges that would have been in that core:
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