This preview shows page 1. Sign up to view the full content.
82. We interpret the question as referring to the field just outside the sphere (that is, at locations roughly equal to the radius r of the sphere). Since the area of a sphere is A = 4 π r 2 and the surface charge density is
This is the end of the preview. Sign up to access the rest of the document.
This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
- Spring '10