ch23_p83 - 83 The field is radially outward and takes on...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
83. The field is radially outward and takes on equal magnitude-values over the surface of any sphere centered at the atom’s center. We take the Gaussian surface to be such a sphere (of radius r ). If E is the magnitude of the field, then the total flux through the Gaussian sphere is 2 4 rE Φ= π . The charge enclosed by the Gaussian surface is the positive charge at the center of the atom plus that portion of the negative charge within the surface. Since the negative charge is uniformly distributed throughout the large sphere
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online