ch23_p86 - 86(a The mass flux is wdv =(3.22 m(1.04 m(1000...

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86. (a) The mass flux is wd ρ v = (3.22 m) (1.04 m) (1000 kg/m 3 ) (0.207 m/s) = 693 kg/s. (b) Since water flows only through area wd , the flux through the larger area is still 693 kg/s. (c) Now the mass flux is (
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