ch24_p13 - 13. First, we observe that V (x) cannot be equal...

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13. First, we observe that V ( x ) cannot be equal to zero for x > d . In fact V ( x ) is always negative for x > d . Now we consider the two remaining regions on the x axis: x < 0 and 0 < x < d . (a) For 0 < x < d we have d 1 = x and d 2 = d – x . Let Vx k q d q d q xdx () =+ F H G I K J F H G I K J = 1 1 2 20 4 13 0 π ε and solve: x = d /4. With d = 24.0 cm, we have x = 6.00 cm. (b) Similarly, for x < 0 the separation between
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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