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13. First, we observe that
V
(
x
) cannot be equal to zero for
x > d
. In fact
V
(
x
) is always
negative for
x > d
. Now we consider the two remaining regions on the
x
axis:
x
< 0 and
0 <
x < d
.
(a) For 0 <
x < d
we have
d
1
=
x
and
d
2
=
d – x
. Let
Vx
k
q
d
q
d
q
xdx
()
=+
F
H
G
I
K
J
−
−
F
H
G
I
K
J
=
1
1
2
20
4
13
0
π
ε
and solve:
x = d
/4. With
d
= 24.0 cm, we have
x
= 6.00 cm.
(b) Similarly, for
x
< 0 the separation between
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
 Spring '10
 Rebello,NobelS

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