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35. The electric field (along some axis) is the (negative of the) derivative of the potential
V
with respect to the corresponding coordinate.
In this case, the derivatives can be read
off of the graphs as slopes (since the graphs are of straight lines).
Thus,
E
x
=
–
d
V
d
x
=
–
©
¨
§
¹
¸
·
−
500 V
0.20 m
=
2500 V/m
=
2500 N/C
E
y
=
–
d
V
d
y
=
–
©
¨
§
¹
¸
·
300 V
0.30 m
=
–1000 V/m
=
–1000 N/C .
These components imply the electric field has a magnitude of 2693 N/C and a direction
of –21.8º (with respect to the positive
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
 Spring '10
 Rebello,NobelS

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