4
7. Let the distance in question be
r
. The initial kinetic energy of the electron is
Km
v
ie
i
=
1
2
2
,
where
v
i
= 3.2
×
10
5
m/s. As the speed doubles,
K
becomes 4
K
i
. Thus
∆∆
U
e
r
KK
K
K
m
v
ii
i
e
i
=
−
=−
−
2
2
4
43
3
2
π
0
ε
()
,
or
2
2
2
19
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
 Spring '10
 Rebello,NobelS
 Energy, Kinetic Energy

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