ch24_p49 - (b) We set K f = 0 and solve for y (choosing the...

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4 9. We apply conservation of energy for particle 3 (with q' = 15 × 10 -6 C): K 0 + U 0 = K f + U f where (letting x = ± 3 m and q 1 = q 2 = 50 × 10 6 C = q ) U = q 1 q' 4 πε o x 2 + y 2 + q 2 q' 4 πε o x 2 + y 2 = q q' 2 πε o x 2 + y 2 . (a) We solve for K f (with y 0 = 4 m): K f = K 0 + U 0 U f = 1.2 J + q q' 2 πε o + © ¨ § ¹ ¸ · 1 x 2 + y 2 0 - 1 | x | = 3.0 J .
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Unformatted text preview: (b) We set K f = 0 and solve for y (choosing the negative root, as indicated in the problem statement): K + U = U f 1.2 J + q q' 2 o x 2 + y 2 = q q' 2 o x 2 + y 2 This yields y = 8.5 m....
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