ch24_p79 - 10 6 m and e = 1.60 10 19 C, we find V P = 1.438...

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7 9. The net potential at point P (the place where we are to place the third electron) due to the fixed charges is computed using Eq. 24-27 (which assumes V 0 as r ): V P = 1 4 πε 0 - e d + 1 4 πε 0 -e d = - e 2 πε 0 d . Thus, with d = 2.00
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Unformatted text preview: 10 6 m and e = 1.60 10 19 C, we find V P = 1.438 10 3 V. Then the required applied work is, by Eq. 24-14, W app = ( e ) V P = 2.30 10 22 J ....
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