ch24_p97 - R = 6.37 10 6 m is the radius of Earth. The...

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97. Assume the charge on Earth is distributed with spherical symmetry. If the electric potential is zero at infinity then at the surface of Earth it is V = q /4 πε 0 R , where q is the charge on Earth and
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Unformatted text preview: R = 6.37 10 6 m is the radius of Earth. The magnitude of the electric field at the surface is E = q /4 R 2 , so V = ER = (100 V/m) (6.37 10 6 m) = 6.4 10 8 V....
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