ch24_p102 - × 10 − 12 J(2 e(92 e 4 πε r = 0(2 e(92 e 4...

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102. The distance r being looked for is that where the alpha particle has (momentarily) zero kinetic energy. Thus, energy conservation leads to K 0 + U 0 = K + U ¡ (0.48
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Unformatted text preview: × 10 − 12 J) + (2 e )(92 e ) 4 πε r = 0 + (2 e )(92 e ) 4 πε r . If we set r = ∞ (so U = 0) then we obtain r = 8.8 × 10 − 14 m....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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