ch24_p102 - 10 12 J) + (2 e )(92 e ) 4 r = 0 + (2 e )(92 e...

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102. The distance r being looked for is that where the alpha particle has (momentarily) zero kinetic energy. Thus, energy conservation leads to K 0 + U 0 = K + U ¡ (0.48
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Unformatted text preview: 10 12 J) + (2 e )(92 e ) 4 r = 0 + (2 e )(92 e ) 4 r . If we set r = (so U = 0) then we obtain r = 8.8 10 14 m....
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