ch24_p112 - 112(a The potential would be Ve = Qe 4 Re2 e =...

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112. (a) The potential would be V Q R R R Rk e e e ee e == = × × F H G I K J =− 4 4 4 4 4 10 16 10 8 99 10 012 2 0 99 π π π π π 6.37 10 0 6 ε σ m electron m C electron Nm C V. 2 2 2 c hc h .. . . (b) The electric field is E V R e === × × 0 8 18 10 . ., V 6.37 10 m
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