115. From the previous chapter, we know that the radial field due to an infinite line-source is Er=λ2π0εwhich integrates, using Eq. 24-18, to obtain VVdrrVrrifrrffiif=+=+FHGIKJzλ2πλ2π00εεln. The subscripts iand fare somewhat arbitrary designations, and we let Vi= Vbe the potential of some point Pat a distance ri= rfrom the wire and Vf= Vobe the potential along some reference axis (which intersects the plane of our figure, shown next, at the xycoordinate origin, placed midway between the bottom two line charges — that is, the midpoint of the bottom side of the equilateral triangle) at a distance rf= afrom each of the bottom wires (and a distance a3 from the topmost wire). Thus, each side of the
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