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ch24_p115 - 115 From the previous chapter we know that the...

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115. From the previous chapter, we know that the radial field due to an infinite line- source is E r = λ 0 ε which integrates, using Eq. 24-18, to obtain V V dr r V r r i f r r f f i i f = + = + F H G I K J z λ λ 0 0 ε ε ln . The subscripts i and f are somewhat arbitrary designations, and we let V i = V be the potential of some point P at a distance r i = r from the wire and V f = V o be the potential along some reference axis (which intersects the plane of our figure, shown next, at the xy coordinate origin, placed midway between the bottom two line charges — that is, the midpoint of the bottom side of the equilateral triangle) at a distance r f = a from each of the bottom wires (and a distance a 3 from the topmost wire). Thus, each side of the
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