# ch24_p118 - 118. The (implicit) equation for the pair (x,y)...

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V = q 1 4 πε o x 2 + y 2 + q 2 4 πε o x 2 + ( y d ) 2 where d = 0.50 m. The values of q 1 and q 2 are given in the problem. (a) We set V = 5.0 V and plotted (using MAPLE’s implicit plotting routine) those points in the xy plane which (when plugged into the above expression for V ) yield 5.0 volts. The result is (b) In this case, the same procedure yields these two equipotential lines: (c) One way to search for the “crossover” case (from a single equipotential line, to two) is to “solve” for a point on the y axis (chosen here to be an absolute distance ξ below q 1 that is, the point is at a negative value of y , specifically at y = −ξ ) in terms of V (or more conveniently, in terms of the parameter η = 4 πε o V x 10 10 ). Thus, the above expression for V becomes simply 118. The (implicit) equation for the pair ( x,y ) in terms of a specific

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## This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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ch24_p118 - 118. The (implicit) equation for the pair (x,y)...

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