12. (a) The potential difference across C1is V1= 10.0 V. Thus, q1= C1V1= (10.0 µF)(10.0 V) = 1.00 ×10–4C. (b) Let C= 10.0 µF. We first consider the three-capacitor combination consisting of C2and its two closest neighbors, each of capacitance C. The equivalent capacitance of this combination is 2eq21 50 C CCC.C.CC=+=+Also, the voltage drop across this combination is
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