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19. (a) and (b) We note that the charge on
C
3
is
q
3
= 12
µ
C – 8.0
µ
C = 4.0
µ
C.
Since the
charge on
C
4
is
q
4
= 8.0
µ
C, then the voltage across it is
q
4
/
C
4
=
2.0 V.
Consequently, the
voltage
V
3
across
C
3
is 2.0 V
¡
C
3
=
q
3
/
V
3
= 2.0
µ
F.
Now
C
3
and
C
4
are in parallel and are thus equivalent to 6
µ
F capacitor which would then
be in series with
C
2
; thus, Eq 2520 leads to an equivalence of
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
 Spring '10
 Rebello,NobelS
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