28. (a) The potential difference across C1(the same as across C2) is given by ()()31212315.0F100V50.0V.10.0F+5.00F+15.0FC VVVCCCµµµµ====++Also, V3= V – V1= V – V2= 100 V – 50.0 V = 50.0 V. Thus, ()()()()4111422244431210.0F50.0V5.00 10C5.00F50.0V2.50 10C5.00 10C2.50 10C=7.50 10C.qCVqC Vqqqµµ−−−−−===×===×=+=×+××(b) The potential difference V3was found in the course of solving for the charges in part (a). Its value is V3= 50.0 V. (c) The energy stored in C3is ()()2223331115.0F50.0V1.88 10
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