ch25_p31 - 31. (a) Let q be the charge on the positive...

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31. (a) Let q be the charge on the positive plate. Since the capacitance of a parallel-plate capacitor is given by 0 i A d ε , the charge is 0 i i qC V A Vd == . After the plates are pulled apart, their separation is f d and the potential difference is V f . Then 0 2 f f qA V d = and 0 00 . ff f f ii dd d A Vq V V AA d d εε = With 3 3.00 10 m i d , 6.00 V i V = and 3 8.00 10 m f d , we have 16.0 V f V = . (b) The initial energy stored in the capacitor is (in SI units) 2 12 4 2 2 11 0 3 1 (8.85 10 )(8.50 10 )(6.00) 4.51 10 J. 2 2 2(3.00 10 ) i i
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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