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# ch25_p31 - 31(a Let q be the charge on the positive plate...

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31. (a) Let q be the charge on the positive plate. Since the capacitance of a parallel-plate capacitor is given by 0 i A d ε , the charge is 0 i i q CV AV d ε = = . After the plates are pulled apart, their separation is f d and the potential difference is V f . Then 0 2 f f q AV d ε = and 0 0 0 . f f f f i i i i d d d A V q V V A A d d ε ε ε = = = With 3 3.00 10 m i d = × , 6.00 V i V = and 3 8.00 10 m f d = × , we have 16.0 V f V = . (b) The initial energy stored in the capacitor is (in SI units) 2 12 4 2 2 11 0 3 1 (8.85 10 )(8.50 10 )(6.00) 4.51 10 J. 2 2 2(3.00 10 ) i i i i AV U CV d
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