ch25_p41 - 41 Using Eq 25-29 with = q/A we have E= q 0 A =...

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41. Using Eq. 25-29, with σ = q / A , we have G E q A == × κε 0 3 200 10 N C which yields q = 3.3 × 10 –7 C. Eq. 25-21 and Eq. 25-27 therefore lead to
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