{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# ch25_p43 - 43 We assume there is charge q on one plate and...

This preview shows page 1. Sign up to view the full content.

43. We assume there is charge q on one plate and charge – q on the other. The electric field in the lower half of the region between the plates is E q A 1 1 0 = κ ε , where A is the plate area. The electric field in the upper half is E q A 2 2 0 = κ ε . Let d /2 be the thickness of each dielectric. Since the field is uniform in each region, the potential difference between the plates is V E d E d qd A qd A = + = + L N M O Q P = + 1 2 0 1 2 0 1 2 1 2 2 2 2 1 1 2 ε κ κ ε κ κ κ κ , so C q V A d = = + 2 0 1 2 1 2 ε κ κ κ κ . This expression is exactly the same as that for C eq of two capacitors in series, one with dielectric constant κ 1 and the other with dielectric constant
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online