ch25_p48 - 48. (a) We apply Gausss law with dielectric: q/0...

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48. (a) We apply Gauss’s law with dielectric: q / ε 0 = κ EA , and solve for : == × ×× × = −− q EA 0 7 12 6 4 89 10 885 10 14 10 100 10 72 . .. C Vm m C Nm 2 2 2 di c hc h (b) The charge induced is
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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