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ch25_p48 - 48(a We apply Gausss law with dielectric q/0 =...

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48. (a) We apply Gauss’s law with dielectric: q / ε 0 = κ EA , and solve for κ : κ ε = = × × × × = q EA 0 7 12 6 4 8 9 10 885 10 14 10 100 10 7 2 . . . . . C V m m C N m 2 2 2 d ic hc h (b) The charge induced is
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