Unformatted text preview: 1 2 CV 2 . The total energy stored by the capacitors is n times that value, and the problem requires the total be equal to 25 × 10 − 6 J. Thus, n 2 (2.0 × 10 − 6 ) © ¨ § ¹ ¸ · 10 n 2 = 25 × 10 − 6 leads to n = 4....
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 Spring '10
 Rebello,NobelS
 Capacitance, Energy, Volt, Inductor, Electric Energy

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