ch25_p51 - 1 2 CV 2 The total energy stored by the...

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51.One way to approach this is to note that – since they are identical – the voltage is evenly divided between them. That is, the voltage across each capacitor is V = (10/ n ) volt. With C = 2.0 × 10 6 F, the electric energy stored by each capacitor is
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Unformatted text preview: 1 2 CV 2 . The total energy stored by the capacitors is n times that value, and the problem requires the total be equal to 25 × 10 − 6 J. Thus, n 2 (2.0 × 10 − 6 ) © ¨ § ¹ ¸ · 10 n 2 = 25 × 10 − 6 leads to n = 4....
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