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ch25_p57 - 57(a Put five such capacitors in series Then the...

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57. (a) Put five such capacitors in series. Then, the equivalent capacitance is 2.0 µ F/5 = 0.40 F. With each capacitor taking a 200-V potential difference, the equivalent capacitor can withstand 1000 V. (b) As one possibility, you can take three identical arrays of capacitors, each array being a
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