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Unformatted text preview: 8 3 µ F, which clearly has the battery voltage across it -- and therefore has charge ( 8 3 µ F)(9.00 V) = 24.0 µ C. This is seen to be the same as the charge on the bottom capacitor. (b) The voltage across the bottom capacitor is V = q C = 24.0 C 4.00 F µ = 6.00 V ....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
- Spring '10