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ch25_p64 - C 1 is V 1 = q 1 C 1 = 36 µ C 6.0 µ F = 6.0 V...

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64. (a) We reduce the parallel group C 2 , C 3 and C 4 , and the parallel pair C 5 and C 6 , obtaining equivalent values C' = 12 µ F and C'' = 12 µ F, respectively. We then reduce the series group C 1 , C' and C'' to obtain an equivalent capacitance of C eq = 3 µ F hooked to the battery. Thus, the charge stored in the system is q sys = C eq V bat = 36 µ C . (b) Since q sys = q 1 then the voltage across
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Unformatted text preview: C 1 is V 1 = q 1 C 1 = 36 µ C 6.0 µ F = 6.0 V . The voltage across the series-pair C' and C'' is consequently V bat- V 1 = 6.0 V. Since C' = C'' , we infer V' = V'' = 6.0/2 = 3.0 V, which, in turn, is equal to V 4 , the potential across C 4 . Therefore, q 4 = C 4 V 4 = (4.0 µ F)(3.0 V) = 12 µ C ....
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