ch25_p76 - 76. (a) The equivalent capacitance is Ceq =...

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76. (a) The equivalent capacitance is C eq = C 1 C 2 /( C 1 + C 2 ). Thus the charge q on each capacitor is 4 12 e q (2.00 F)(8.00 F)(300V) 4.80 10 C. 2.00 F 8.00 F CCV qq q CV CC µµ === = = = × ++ (b) The potential difference is V 1 = q / C 1 = 4.80 × 10 –4 C/2.0 µ F = 240 V. (c) As noted in part (a), 4 21 4.80 10 C. qq == × (d) V 2 = V – V 1 = 300 V – 240 V = 60.0 V. Now we have q' 1 / C 1 q' 2 / C 2 V' ( V' being the new potential difference across each capacitor) and q' 1 + q' 2 = 2 q . We solve for q' 1 , q' 2 and
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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