ch25_p78 - 78. (a) The voltage across C1 is 12 V, so the...

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78. (a) The voltage across C 1 is 12 V, so the charge is qC V 11 1 24 == µ C. (b) We reduce the circuit, starting with C 4 and C 3 (in parallel) which are equivalent to 4 F . This is then in series with C 2 , resulting in an equivalence equal to 4 3 F which would have 12 V across it. The charge on this
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