ch25_p79 - we observe that the 8 F equivalence from the top...

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79. We reduce the circuit, starting with C 1 and C 2 (in series) which are equivalent to 4 µ F. This is then parallel to C 3 and results in a total of 8 F, which is now in series with C 4 and can be further reduced. However, the final step in the reduction is not necessary, as
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Unformatted text preview: we observe that the 8 F equivalence from the top 3 capacitors has the same capacitance as C 4 and therefore the same voltage; since they are in series, that voltage is then 12/2 = 6.0 V....
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