{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

ch25_p79 - we observe that the 8 F equivalence from the top...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
79. We reduce the circuit, starting with C 1 and C 2 (in series) which are equivalent to 4 µ F. This is then parallel to C 3 and results in a total of 8 µ F, which is now in series with C 4 and can be further reduced. However, the final step in the reduction is not necessary, as
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: we observe that the 8 F equivalence from the top 3 capacitors has the same capacitance as C 4 and therefore the same voltage; since they are in series, that voltage is then 12/2 = 6.0 V....
View Full Document

{[ snackBarMessage ]}