{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

ch26_p14 - 14 We use R/L =/A = 0.150/km(a For copper J =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
14. We use R / L = ρ / A = 0.150 /km. (a) For copper J = i / A = (60.0 A)(0.150 /km)/(1.69 × 10 –8 ·m) = 5.32 × 10 5 A/m 2 . (b) We denote the mass densities as m . For copper, ( m / L ) c = ( m A ) c = (8960 kg/m 3 ) (1.69 × 10 –8 · m)/(0.150 /km) = 1.01 kg/m. (c) For aluminum
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online