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24. The absolute values of the slopes (for the straightline segments shown in the graph of
Fig. 2626(b)) are equal to the respective electric field magnitudes.
Thus, applying Eq.
265 and Eq. 2613 to the three sections of the resistive strip, we have
J
1
=
i
A
=
σ
1
E
1
=
σ
1
(0.50
×
10
3
V/m)
J
2
=
i
A
=
σ
2
E
2
=
σ
2
(4.0
×
10
3
V/m)
J
3
=
i
A
=
σ
3
E
3
=
σ
3
(1.0
×
10
3
V/m)
.
We note that the current densities are the same since the values of
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Unformatted text preview: i and A are the same (see the problem statement) in the three sections, so J 1 = J 2 = J 3 . (a) Thus we see that σ 1 = 2 σ 3 = 2 (3.00 × 10 7 ( Ω ·m) − 1 ) = 6.00 × 10 7 ( Ω ·m) − 1 . (b) Similarly, σ 2 = σ 3 /4 = (3.00 × 10 7 ( Ω ·m) − 1 )/4 = 7.50 × 10 6 ( Ω ·m) − 1 ....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
 Spring '10
 Rebello,NobelS

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