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ch26_p30 - R =(1.00 Ω(25 ft/1000 ft(4 2 = 0.40 Ω.

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30. We use R L / A . The diameter of a 22-gauge wire is 1/4 that of a 10-gauge wire. Thus from R = ρ L / A we find the resistance of 25 ft of 22-gauge copper wire to be
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Unformatted text preview: R = (1.00 Ω ) (25 ft/1000 ft)(4) 2 = 0.40 Ω ....
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