ch26_p30 - R = (1.00 ) (25 ft/1000 ft)(4) 2 = 0.40 .

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30. We use R L / A . The diameter of a 22-gauge wire is 1/4 that of a 10-gauge wire. Thus from R = ρ L / A we find the resistance of 25 ft of 22-gauge copper wire to be
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Unformatted text preview: R = (1.00 ) (25 ft/1000 ft)(4) 2 = 0.40 ....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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