ch26_p31 - × 10 –6 Ω = 1.59 × 10 –8 V(c The...

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31. (a) The current in each strand is i = 0.750 A/125 = 6.00 × 10 –3 A. (b) The potential difference is V = iR = (6.00 × 10 –3 A) (2.65
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Unformatted text preview: × 10 –6 Ω ) = 1.59 × 10 –8 V. (c) The resistance is R total = 2.65 × 10 –6 Ω /125 = 2.12 × 10 –8 Ω ....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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