ch26_p32 - Conservation of electric current from section 1...

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32. The number density of conduction electrons in copper is n = 8.49 × 10 28 /m 3 . The electric field in section 2 is (10.0 µ V)/(2.00 m) = 5.00 µ V/m. Since ρ = 1.69 × 10 8 ·m for copper (see Table 26-1) then Eq. 26-10 leads to a current density vector of magnitude J 2 = (5.00 µ V/m)/(1.69 × 10 8 ·m) = 296 A/m 2 in section 2.
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Unformatted text preview: Conservation of electric current from section 1 into section 2 implies J 1 A 1 = J 2 A 2 J 1 (4 R 2 ) = J 2 ( R 2 ) (see Eq. 26-5). This leads to J 1 = 74 A/m 2 . Now, Eq. 26-7 immediately yields v d = J 1 ne = 5.44 10 9 m/s for the drift speed of conduction-electrons in section 1....
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