ch26_p44 - found from Eq. 26-26: P = iV = 210 W. Assuming a...

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44. Assuming the current is along the wire (not radial) we find the current from Eq. 26-4: i = ´ | J | dA = 2 0 2 R kr rdr π ³ = 1 2 k π R 4 = 3.50 A where k = 2.75 × 10 10 A/m 4 and R = 0.00300 m. The rate of thermal energy generation is
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Unformatted text preview: found from Eq. 26-26: P = iV = 210 W. Assuming a steady rate, the thermal energy generated in 40 s is (210 J/s)(3600 s) = 7.56 10 5 J....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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