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4
5. (a) Using Table 261 and Eq. 2610 (or Eq. 2611), we have
()
82
62
2.00A


 
1.69 10
m
1.69 10 V/m.
2.00 10 m
EJ
ρ
−−
−
§·
==×
Ω
⋅
=
×
¨¸
×
©¹
GG
(b) Using
L
= 4.0 m, the resistance is found from Eq. 2616:
R
=
L
/
A
= 0.0338
Ω
. The
rate of thermal energy generation is found from Eq. 2627:
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
 Spring '10
 Rebello,NobelS
 Resistance, Energy, Thermal Energy

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