ch26_p50 - i/A = J = constant. Thus, the answer is “yes,...

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50. (a) Circular area depends, of course, on r 2 , so the horizontal axis of the graph in Fig. 26-33(b) is effectively the same as the area (enclosed at variable radius values), except for a factor of π . The fact that the current increases linearly in the graph means that
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Unformatted text preview: i/A = J = constant. Thus, the answer is “yes, the current density is uniform.” (b) We find i /( π r 2 ) = (0.005 A)/( π × 4 × 10 − 6 m 2 ) = 398 ≈ 4.0 × 10 2 A/m 2 ....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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