ch26_p59 - 59. (a) The current is V V Vd 2 i= = = R L / A 4...

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59. (a) The current is 2 22 8 /4 V)[(0.0400in.)(2.54 10 m/in.)] 1.74 A. 4(1.69 10 m)(33.0m) VV V d i RL A L ρρ π == = π(1.20 × ×Ω (b) The magnitude of the current density vector is 62 2 44 ( 1 . 7 4 A ) | | 2.15 10 A/m .
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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