ch26_p67 - 3600 s) = 1.46 10 5 J.

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
6 7. We find the rate of energy consumption from Eq. 26-28: P = V 2 R = 90 2 400 = 20.3 W . Assuming a steady rate, the energy consumed is (20.3 J/s)(2.00
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 3600 s) = 1.46 10 5 J....
View Full Document

This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

Ask a homework question - tutors are online