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ch26_p67 - × 3600 s = 1.46 × 10 5 J.

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6 7. We find the rate of energy consumption from Eq. 26-28: P = V 2 R = 90 2 400 = 20.3 W . Assuming a steady rate, the energy consumed is (20.3 J/s)(2.00
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Unformatted text preview: × 3600 s) = 1.46 × 10 5 J....
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