ch26_p75 - 75. (a) With = 1.69 108 m (from Table 26-1) and...

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75. (a) With ρ = 1.69 × 10 8 ·m (from Table 26-1) and L = 1000 m, Eq. 26-16 leads to A = L R = (1.69 × 10 8 ) 1000 33 = 5.1 × 10 7 m 2 . Then, A = π r 2 yields r = 4.0 × 10 -4 m; doubling that gives the diameter as 8.1
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