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ch26_p79 - 79(a In Eq 26-17 we let = 20 where 0 is the...

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79. (a) In Eq. 26-17, we let ρ = 2 ρ 0 where ρ 0 is the resistivity at T 0 = 20°C: ρ ρ ρ ρ ρ α = = 0 0 0 0 0 2 T T b g , and solve for the temperature T : T T = + = ° + × ° 0 3 1 20 1 4 3 10 250 α C K C. . / (b) Since a change in Celsius is equivalent to a change on the Kelvin temperature scale,
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