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79. (a) In Eq. 2617, we let
ρ
= 2
0
where
0
is the resistivity at
T
0
= 20°C:
ρρ
ρ ρ ρα
−=
−
00
0
0
0
2
TT
b
g
,
and solve for the temperature
T
:
=+=°+
×
≈°
−
0
3
1
20
1
43 10
250
α
C
K
C.
./
(b) Since a change in Celsius is equivalent to a change on the Kelvin temperature scale,
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
 Spring '10
 Rebello,NobelS

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