Solution-HW1_Spr10_ 1 - MGMT 305 Homework #1 Page 1 of 4...

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MGMT 305 Homework #1 Page 1 of 4 MGMT 305 Spring 2010 Assignment 1 Solution (Chapters 3, 5, 6) Chapter 3 1. (Total: 12 pts) a. Public Transportation: Automobile: (4 pts) b. Public Transportation: s = 4.64 Automobile: s = 1.83 (6 pts) c. Prefer the automobile. The mean times are the same, but the auto has less variability. (2 pts) Chapter 5 2. a. f (12) = .1144 (1 pt) b. f (16) = .1304 (1 pt) c. P ( x 16) = f (16) + f (17) + f (18) + f (19) + f (20) = .1304 + .0716 + .0278 + .0068 + .0008 = .2374 (4 pts) d. P ( x 15) = 1 - P ( x 16) = 1 - .2374 = .7626 (4 pts) e. E ( x ) = n p = 20(.7) = 14 (2 pts) f. Var ( x ) = n p (1 - p ) = 20 (.7) (.3) = 4.2 (2 pts) σ = = 2.0494 (1 pt) (Total: 15 pts) 3. Binomial n = 10 and p = .09 a. Yes. Since they are selected randomly, p is the same from trial to trial and the trials are independent. (2 pts) b. f (2) = .1714 (2 pts)
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MGMT 305 Homework #1 Page 2 of 4 c. f (0) = .3894 (2 pts) d. 1 - f (0) - f (1) - f (2) = 1 - (.3894 + .3851 + .1714) = .0541
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This note was uploaded on 01/31/2011 for the course MGMT 305 taught by Professor Priya during the Spring '08 term at Purdue University-West Lafayette.

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Solution-HW1_Spr10_ 1 - MGMT 305 Homework #1 Page 1 of 4...

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