# HW4sol10 - ECE2280 Homework#4 Solution Spring ’XDI O...

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Unformatted text preview: ECE2280 Homework #4 Solution Spring ’XDI O 1. "Analyze. the circuit shown below ta determine the voitagas a: the drain, V , at. the gate, Va, and at the source, V5 Find the currents thmugh all branches (gate current, Hg, drain curreni ha, and source current 13-} Lat VFIV and ku’iIWILF] mAN”; Negiec: the channel Bengt}: modulatien effect (it: J‘s-'0} +§QV \fﬁj :, '3 ‘x/ 133311; ‘ I, 1 191:5 : ghw‘iﬂgkavm l, 5 . ’~ \ -,. 2: flhﬂ titlf“é‘> Lg‘b P, {4‘[email protected]? Eylrgfp ’Zlcrbﬂéio “yard-ﬂ" —— “Mug 1‘5 :9»??ng 4-6!" H 1 f A 3“ ﬂqu'j' l ‘: Lt‘hr‘lhqﬂ m“? 71%qu L131 a: mm; sammi 13:1 dim-:91, and 3%). {.21} Draw the; smaH-égrsai squivahmﬁ. circuit; by assuming an cagmciim-g {magmasfigs-"Lg. {Ea} Anaiyze E‘i‘aE: circuit In ﬁnd ﬂw‘ﬁg‘ﬂn, Enigma»? tﬁﬂ} and [um "I Miriam“) m Oxidefﬁm 62"} _ D Semitméwdw (5-3;; , ' c3 5 gﬂuf'gt {Cur6§n+ ngams ;f\h-%V,M5\$FW “bunt @Vas > Vé , 3. ® Vim =¥= O V _ , N0“: 1-? v.53 {<9 4&10- TH»; “5501be .. bﬁmms Ha dram an} 'Hu dra‘m CECQM W sauna. 3mm. W Maui-TE? as shear: is“ \$3MM+ Fiﬁ“ (11\$ +f‘M RM ckagcmm . +Mﬂ5;3 fag Sinai + 41“, 22c: m) M5 ’3 “SW3 m o a l nae-142 ’55 r/If’avﬁto‘ (ELL-«WA incomSté ,ad- hear! ’%.5:\$4M ”31‘7” a.“ direchcms3 93% wag-5,24 ya: 1;, 75 mfg“. m ’ LSD-V Fﬂiaﬁ'bngﬁp .35 Shaun or: HQ. 43W?“ IQ. is chara¢+ariaa§ has “Hag \$oltow3n? e‘ﬁuﬁﬁan‘ . ' _ 1‘ w“ I 7" ﬁns" kn I: [(Vc—a“vé)vvs “ E V03 ‘ NW3 / , kn: C ff Egkfﬁ‘m MOB”; ‘ ¢g . ﬂ” 0 X n Semican Marigmnﬁw :0" . . x C {-1 4+: a ﬁshnet r W... 1.; @15ch (“£330 a, an??? Zaﬂ amp-e L (Car 3" g6}; fiéax} W a Chamnﬁ‘ 901613, 1‘39“ 30ﬁ§dm +£3ch Ls: chum”! ham 4.)) 50x Ei’YI-‘it Fgrmﬁﬁvi}? \Iée: threshold “AW SW'f‘fan PE" 6' ! : Q’W 2 ébsil‘n 1—625‘4) Inducw‘ Chamml if: Lima A EA. 5 --1 “Mi - '~' ;h¢:>'}\::va a»??? \$099M? ﬁg Ema Wa L“ N“ Ya m mamm Wr+1l4 4% wolfnyz.‘ “may . 'aiqill'ﬂ“ 5m! hwy; b' ' '° i ﬁm' *3 M am:- my: 14348? 41.x 15‘ 2&3: 0 +351 ﬁm um: g“Ce * £5 Gig Sim‘h . éﬁf‘aﬁléﬂshxf‘ a? «TﬂogsFeTnEam 3: F' “M ’1"; dz 4+)“ 9 7:43:31} 430:" Vafrsyouszqiait‘bgg' W Sq“ VG—S’ » 7 ’50 WWES 15,0 VMiFeS v53 VquIﬂS V135 Varies A + ' “* . V68 (Ions in? 7 . "116\$ Warm; 3 ® W35 '15 "Hex; Esq‘i'ﬂf‘ +§an [35% 1"» wk; 5. \9 ‘1'} V , |l5 Mei cant-ﬂaw; and Q95. Is Varigel 03 . AgV ngUVOhg 9A, smuw med: 67mg; 7 47; 4 \$903 15 halt}: in ﬁx; an “\$15.: subs‘f‘m‘c‘t git) * 3+ Musi- £91ch a ﬁg ckannx} An NMOS' “£115”. iﬁ a: Q“ 1357‘“ \$m£\$4rq+n 5° +in+hL Y Muse'- ' Qlowswcé 47 (W n. Use: Vt=lV _ kn’(W/L)=2AN2 A=0 for all transistors The 4A current source is not ideal and may have a voltage drop across it. For DC analysis, assume that the capacitors act as open. Solve the circuit for the DC values: (a) The Q-point for transistor M2 = U6 § : 3 2/ 03) V52 : ‘1 V (aria: (d) Voz = (e) erify that the transistor M2 is saturated. 3% éwb l 436% 3 “W73“ fhl 3.0 It) : EEC”) (Vexrlje) ZCI‘XAés) ,1“ - \j, .- 1, (m : o / Um - m7. ~ 3 ,— Z. st ’ E13 "‘ (6“ Z '2. , z. _ ,, 2 g jp >(0 (3143 10") I) (vﬁ: ZI“ - * 4,1“an ~~ H ‘2 13 J: c— 8( :1: 0 at» 2 13 (’_:_~__ ? (5») - .5 3/“ ' z. 13: 5 L3 3- 145— , VD mugwwm : 3 .. ’37 t\ 1‘ Ht \$M"‘"‘”"‘ “bx 4a-; /‘1 ,- - [£1 7-K 9 V‘Bl = £30., [GU MA} @7/4 7“»?S‘r'1 aces we“ Wk; ” 29'154! if: E: am»! 113 7t 1/51“»ti 5/615 ; 21v >vé / {7a- .., W > {Hi/~10 / a, N39M.’ Wk 31%: o 3:” 2— L k {a} (U ~ Whit/'6 2 M L 075 4. ﬁg; “>5 ...
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