Final_Fall07_Key - CI'SIOI 4 FINAL EXAM Fall 2007 CHEM 3369...

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Unformatted text preview: \' CI'SIOI] 4 FINAL EXAM Fall 2007 CHEM 3369 December 10, 2007 5:00 — 8:00 pm This exam contains 35 questions. Mark the choice on the answer sheet corresponding to the best answer for each of following questions. You can neglect the activin coefficients in all questions. N = 6.022 x 10”; Charge of a single electron = 1.6022 x 10—1 9 C: 2.303RTIF = 0.05916 V; F = 96,485 Cltnol e— Czttculale the pH of 0.020 M BuiOH};(nq). lam 3 2 .._fi;‘.:‘> F3 + 'T ' ‘; 2 —-t k A. ‘ . _J t‘) I _I’ ' \‘l-I—n‘. l a" t-«\ h B. 12.30 t?” 5 [LE " _ . lib -: 2-in-3“ " 3‘}. @1160 T \Li " LEV} pe t -. 2.1m,” - til J U \_ ' D. [.70 _‘ l‘ . 1 3H.- . l, I. E. |0.78 4 \?.J a; 1 I. V t a: — - '\: , 3 —-’ t" I ': ( 3. Which ot'tlte follouing is the strongest base. (we I: - -‘ ., -\. "-IVJ \ A. urea tpr = 13.901 B. ammonia [pKh : +75! C. morphine [pl-(1, = 5.79) D. p} ridine itth = 8.75] menu-[amine (pr = 3.4—1] , . . . 1-_ . . . . . . .1. B_\.' ho“ mun}. tolls “ill the pOiCIIlifll u] an Mg— IOI'l-SCI‘ISIUVC electrode change it the electrode is remoted l'rom sumo-4 M MgCl; and pleced in moxie-5‘ M sthtg‘.‘ f J a-i ' \ _ a a . l. 'A. +0059: \-' 5 v '7‘) : 'qu 3“ 0 .7“ q 9 . (3) +0.02% v ‘v = .. / H " "J C. + 0.1133 \-' "' r) q _-.-“ D. —2.360 \' “"2 ‘ a " " . E. no change will hedetected i. . .3 7' M 4. It“ the solubilit) of calcium fluoride in tuner is 2.2 .\ 10—4 :\I. the Ksp ot‘calcittm l‘lttoride is e. . . 2.2.\ 10-4 _ 5a. . - I _' -'" J ' ‘1 9 . —II .5 . "I" j -‘ w. .- B. L] .\ to ‘ j _ . f x c. 1“» 7 e k;- C. 4.8x It'l-b ‘ L a s _ - x. D‘ x IU-I—i ' - _ 3' "2' M r'\_-" . i—i {‘- ‘L 4.3 x to-H I, '5 u... _: . \/5. AG“ for the reaction -— ct; 3005'; + 2N03—[aqj + 8H+tjnqt —+ 3(Tu3"tt'tqjll +3\’Ot_'g_t + —lllgOtIi f _’ t'i- 451. Lo" at 298 K is —359.2 kJ-mol— 1. The standard \oltage obtainable from a cell based on this reaction IS @ 0.62 \' a a? i .. n ‘9 E,” ' - "395’: .afiijrjfifid .J' B. 0.93 \-' ‘4 9. 1 5;}; C. 1.24 \r J. E, *- W ,x 1). 1.86 v #3:»:- ‘I v, r 7:2 v 779‘. Q -- 1-2. 3.72\-' -. _f. . .... =1. _i..f‘ I‘J'I'“. L..1 I 1.. Ff I 332m L 1 '9. 0/What is the pOH of the solution that results when [0.0 ml- of 0.0835 M HCI um] [0.0 mL of 0.0850 M NaOH 3 '- r} .- aremned. _O[ L 1/068351-21, 91.; t 1- dflgflua “4 A. IOBS L. FM H ‘au 3- 1-07 '0‘ Y O-¢?531}~0\r.42_g\7‘1r saute W ~ rl H1 C. 7.00 q “5"” 5 D. 12.93 - . _F . _ / _ @112 ,g_‘:fh°a.t1 'l‘s‘to Mc7-5xLO M r »lo./J[f£_fi< ./ [m —. 3m 7. For the reaction_ INHJHS‘J‘) H NH3(gJ + Hgstg‘) KP = 5.6 \' I02 (‘1 900 K. Slaning with pure NH4HS, the equilibrium pressure of H25 is 0 O 1'1? 1: [Ntvia 3i¥i25 FI\ A. 230 film a, w h. ‘3 13. 560mm C r. x X. tag : (151:1: \ 24 alm H x j: X 1' D. ['2 alrn E _ X 1“ v ' _u__ _ . _3 . '- \/E. [.85 IO alm :\< :{Zg-(Lfi\\ ._ _.1 -—-_> 8. thgmggggfigo_lhe_el_e§_lrode at \\-'hich[redueliorfoccurs as @the cathode B the anode I _ q _-* C. the reference eleclmde "- I _f___- 7:. I). theion—seleclireeleclrode _ q + E. the indicaloreleclrode Sn 2""- + Sn"I ' e.___ / . _ . _ a (.9350 (no) 9. Calculate l: for the following cell at 25°C [aqueous SOIUiIOIl). ' H w ___ a. _. _ __ . .- Pt I Sn2+(0.40 .141. Sn4+{0_}0.-U_l 1| Sn 510030111). Sin—10,010.10 I Pt .- 34 ” . a; A.0v ,‘__ r 93:41”: m 0.032 V C "r L g4??? "L _ - u \ C. cum I my, \ 2,-5.1]; Lot-01 .1). 0.l82 v : [01o a '1 is! )0...) FL H- 9 . .r ~ -~:;-""—""'“"'" " ' E‘ 0-H” ‘ .1. 9111500 =10 3 \/ 10. The pH ul‘a solution that is 0.12 M (‘6H5NH20‘1qJ (K = 4.3 \ 10m) and 0.018 M ("gHgNHgf‘luiql is A. 355 LG?“ N 1’" H130 -- 5.1.5154 HgNHfIII' “i 13. 10.19 -— val-'1' .. -. ' 3.82 PL‘i'?H“ L {5-555 J ,ogglwy‘vrt . 5.46 : H- ‘3‘ SU‘ 5%.:m'77'” E. 9.37 .— ’, ,in e "gap - g {UH-3. I ‘7 L1l5’r\,0 : niawt l I. If the. pH of 0.20 M CHgN‘Hgtaq) is l |.93. the percentage of base ionized is .y _ J . A. The Kbis requiredinorderlodoihecalculaliori. f w.) "' 1;" “1 5.9.x io-lce- .1514 -: 91‘; poi-l : 4“? 5'3 2.13%“ 5 [:3 +1 {X . 4.3% .I __ 1.1.1 v 9 ll, '1 I). 43% M? ~57? I ' '3‘" :7 LAVA 13°“ : — tofii'ofig — ' - . on 10 [3. 83.6 -r 2 _‘J'j fl fr ’- g I {.3 ' :— 3. 1 [2. The Species capable ofoxidizing \='2+ \\=i1houl0xidizing BF is | A. Fe3+ . . 1 l .05 4* 'l I" : i __.__ .E-a. " t B. Zn—T' C P. 1". Z {Th/C) >3 C 3’- % _ If __ n . \Lb : L015? \3 “Wm- E. Mn-+ ##fl” _r__F,, I. ’\ a?” .. walk) L'L- Z . - -. II 'I I___\ ‘_ 7 / Hrtil '1‘ A, L235 94:: u {‘59 v ' X 5 2 J) ‘ ;. v ' ' J‘- _'.- i L: D / I”, T .— ' ' ' ‘— i I' I3. The equilibrium constant. KP. for [he reaction 21-1305} 9 EHgU) + 02(3) i5 |.2 V 10—30. Calculalc KP for [he reaclion Hgfl) + lflOgig} H 1-1306} 9.] x 10” B. 8.3x1029 (i. LI x 10-15 D. —l.l .\ [0"5 4.2 .\ 1039 / l—l. Given: q ‘9 7 -q a. .I’ ‘1 —'|— a) f x." J )—|- 502(3) H 02(9} + S{s') 51:25 x 10—3) ){5 J . '30)) 503(3) 6 [5203(3) + 303(3) 1x",2=--1.{)x10—[3 ’g/Kfiifil, {3-3 a.) :5 Calculalu K for Ihc rcaclion 28(5) + 303(3) 1':— gsoflgl a _____.. g- _ _ A_ 1_6X I040 ll (/11 _-__.J\__' ' j . _ - . - L_“ _ B. |.0.\ I063 14 4 f“ I. @IJ X It)130 ' 1 My D. |.6 \' I030 E. 1.0 x I0‘03 I/ 15. Consider the reaction 2503(5)] + 03(3) (—1 2503(3). If. initially. |SO3| = 3.2 mM and at equilibrium ISL—)3 | = 3.0 mh-I, calculate the equilibrium conccnlmlion ol‘ 0.1. A. [.8 mM B. 3.3 mM ‘ 3.0 mM L5 mM H. \,-’ V/ I E. 0.30 mix-I ' ' I6. The cell diagram for me rcacliun in which h}-‘dr0gcri gas reduces (fugiaqi is ’ .__:.---. 3 f’. I}: I Cu3*(aq) I 143(ng II Hwqu Pl 3/11: l (1u2+{aqilH+cjaqiungrgiIPi (M 2‘!“ , a, C _. .. 5x. {I . -' or. . '3- . y . . . k’ l' u I “I.” "x ‘ Cu(5) | Cur-rag) ll Hfl‘aq) | l-Igig) | PI ’0’.) Pl I I"12(g} I Hfiaqi 11 Cu2+(aq) I 01(3) / /' curs) l Cu2+{aq) II 03(3) 1 H2(g] 1 Pl l7. Which of [he fallen-mg solulions gives a pH greater than 7'? 10-8 NH3 B. 10-8 HCI C. 10-3 HCOOH D. 10-8 CH3COOl—l E. 10—3 KC] ./ E8. How many millilitch of 0.0250 M KOH an: required to neutralize 5.00 mL of 0. “[13 M HBr'.’ 2- C 07,; my 5 O is) . 3...m_ ‘ Q . A: . .' 'k-QL- 18.4—1th /{ O (i? 2|.6rnL _ l:. 2.3] rm. f 19. 'l'hc pOH at {he hall'—sloichi0melric point for lhc titration 010.23 M aqueous chlomacclic acid {K3 : 1.4 x 111—ij with 0.10 M KOHi‘aq) is A. 3.51 @1115 C. 1.74 13 1.92 F 2.85 Ix.) F3 What species is Oxidized in the following rcaclion‘.‘ 20(5) + 30111026} + 12H+('aq_) —'» 2Cr3+(aql + 30111210qu + 6H20U') <52 . MUG; (‘r-h- H+ H20 mp0 21. Whaldocs 1hr: use 01‘ LcChalclicrs' principle cnflhlc us to prcdicl about 1hr: l'olloning rcaclion at cquilibrium whcntllc pH oflhe solutionis dccrcascd'.‘ Br03— + 2Cr3" + all-[20 +6 Br— + (71-3072“ + SH':' / “’1 . I. . \rfl 1:15? ‘ _/__ - 3 it“; '3 g the mar-{lion “I” shift [0 the left .4 r H , X 1 @fig‘l B. then: “'1” be no change ‘ :9 _ - a «Z? . Q the rcaclion will shift 10 [he righl .'\ /."' ‘ I ..-*‘"\\ I k :3, _..\ Q I‘- .\ . llicrcis notcnoughinfflrmation gii'emc- p‘gedicl “7‘ if“; 43‘ " - ‘_ E. none of the above. an3\\'crs arc. "orrccl *5 “ .. ' I... “I. y. Y A ‘ 3 ___ \/ ilk-E.“ 1 ’K‘qu J 22: How man) milliliters 016.123 M HCI should be added [0 213 ml. 01‘ 0.00666 M clh_\|aminc lCHgCHQNHg. 7 pr = 3.364) to 31w 3 pH of 10.52? A, A. 3.27 ' 32.7 C'. 6.54 ___ D. 16.4 f__. I’ . 3.. 21.3 ' 3-. x/ J" H. " i ‘23. Hcm man) significant figures are in the numbcr 0.005520”? A. 2 . 3 4 D. 5 E. 6 24. 196110.02] + 1.58 (10.03;: — 0431:0011 = '? ——~-- -- --———"";‘”’"““" -" E’I.Iil0r E , r a, a k 3.0mm l 6W? 1L 1% w L 1 L4 . 3.0610041 I J fsiiom 210d 1 ‘ 12.5,. A solution made up with equimolar concentrations of weak acid and its conjugate base has a pH of 6.35. What is theK fortheacid? ,) . A a Flt». PM -+ {- Q‘M/‘l \ 3M 4957 We . 1.1 s [0—6 _. . . $4.5 x l0‘7 ‘7 t): 1-, \N’ _ furl lg. :2) c. 8.9x 10-7 Z " D. |.0s]0—7M ,wt 5 mil E. need moreinformation to tell .. (“‘91 / “I ~{ "oz no "'7 26. A mixture centaining 0nl_\_-‘ Alng, {RV 101.96} and R303 (159.69) weighs 2.019 3. When healed under a stream of hydrogen. the Al303 is unchanged. but F6203 is converted to lmctaliic Fe plus H30(gl. il‘a residue ; weighs [.529 g. what is the “=th of F6203 in the originalgwufi? "" .’ '--- 3 Zple .g. -' ' ' ' 'd a 1 ‘n I u fl - “r v’n) “14“”? m L mt fit-w) i i'\_1(17°t-Lfi0Lt ~— -' “at”? .pi. 1 59.6 “1% A B C. (6.7 80.8 0.1% / 20.2th0 I" t . . 7’ ‘ attxt’OHWJ + 2N¢C55J7> sl' “'7 E. 63.8 mt. I I' 3 4911' ;—-":' l: L .t 59 '3‘, w ' ‘27 on man}. moles of AllOHt}. (Kg? = LOUD—33) will dissolve in a 250-mL solution in which the pH is fixed <14 at5.l2?. Qmofih fl: fife"; ) Wad/q -: lfiifil l7 ’ MM is A. 2.3 x IO“9 1 w 5‘ 0,, 3 _ 1.! x [0-7 53¢ :. 2, !'3' 1. iii-3H3 "t '5‘; k4 . ' \L’ .fi\)" (- 8" k .— f‘ u;— ‘j 5 iv- ; é“ 3 I - = I' I "J I In) \I’ ’- l I Z’ “ :' A: ’5 D. 5.2 x 10-! l- ‘-* '- "“" i 1 ' I '-—“g_?"” cw.- fiif @44 x [0-7 7 - 3‘" ' W43 5:, 2 . misture consisting of 0.250 M N2 and 0.500 M Hg in areactirm vessel at certain temperature reacts and 3“. ‘ It?“ "a. reaches equilibrium: 052(3) + 31-13(3) H- 2NH3(g). Atequilibrium. the concentration ol‘alnrnonia is 0.050 f -:L . > M. Calculate the concentration of H3 an equilibrium. I .. r cf £3 .-,. s . / ,1 ;.: l. ‘3 l’ LO a; A. 0.333 M N fink/Ag ,-, 230%; 1040-32 : . ,7“ -’- ', 0 8. 0.225 M ,- ,3, ' ‘ :19 -—- —.; k ., 2 3 J C. 0.275012» 5 7.x ‘S'w’t’ ”' H r it" 0425 M "‘ —-~—H-....c..HH‘ .0 f9 , K N f H . t - h) - " an" " “HE—a- .)‘3 ‘ BvIO F— i’ "' h l\_‘ -. 0.230 0'} ‘5 -.;-'-“"‘ p’r ##3#1‘3y; t J .25 2 x :. . 4513/ ‘34 Which cme of the followmg gives a 0.10 M solution with the highest pH? (i\ Z A. Since all are acids. the pH is the same for all solutions. k '5 a; B. HF (pilt'a = 3.45) ! r'i ‘ j H3P04 (pit'al = 2.12} LN 1/154,“ “1 . CH3COOH (pKa : 4.75} H103 (pKfl = 0.77) .10. What is the pH of SCfl\\'21lL‘l' that has a hydronitim ion concentration of ].-l \ I0—5 M? 5.22 i H13 4.85 i (I— ‘- "I" C' 8'78 5H 3 “f D“? .' ' Q»; \t , II EPA-i K "- ' "’ s»? a v Du C. {if } 1 _ _ YEK '\' “'5' . _ . CaILulale the some strength of th aqueous solution .5 .11. What is the cathode reactioa rr______ . Pt(5) | H.3th HClt‘oq) n H3; -120} | age) ' %Hg(g} a 2H+iaq) + 2r [fem —» Ptlwq) + 20- C. ZHgU) + '2Cl‘tloq] -) HggClgls) + Ee‘ _ —= 2Hgtt'} + 2Cl_(aq) y‘ZHClfiiq) + 2:? —1 Hgtg} + 201an for the cell represented by the cell diagram that l‘ollou-s‘? "' at "Lab J — . . - gin J _ J: 1'- — I 1'; —*._ _-, c- i; Annuity is a designation of corieentration expressing K. a f the number of moles of substance per kilogram of solvent the number of moles of substance per kilogram of total solution the number of moles of substance per liter of total solution the number of moles of substance per liter of solvent .13. The reaction mixture of 2A + 213 (-3 3C + D is analyzed and it is found IA] = 5. |B| = 4, |(‘[ = 3- and [DI = 2. If X: 0.5, what is the Slate ol‘ this reaction? ' “ "- .._ . - :r' 13,071" igv" A equrllbnum has been reached 3 4 1L n (L r‘ ' ,fi @e reaction needs to proceed to the right 3r 5- fl ‘ 1‘ (ye. “3* the reaction needs to proceed to the left fr 2, 'u {/- ‘ 9’ x..- U t- 4 D. itis exothermic a I) k /‘ F. none of the above is correct 3" g "1 “hr—I“ _‘ 34. The solubility of AgCl [it/5p: L6 it 10-10; in 0.50 M N00 is {09 ' “S A. L3 x 10-5 M 6- .q ‘fl ' 35 s - t ' vi “ - i __ B. 8.0x 10r|0 M ‘90)“ {'9 mg? ‘* 01‘ “ x ' _ g. 3.5 .1; 10cm M n .. .- f L #45; f. _ _|0 _ A r" .rw‘x .1 {A Q a h s... . 1.6.x”) M “as, Ti“)er a I}. m LAf H— - . .4 -S Q @32xl0‘ M ' .» -- ' ‘e- r it 5 \f . so A containing 0.020 M of 0.012.. 0.030 M of NaN-Og. and 0.040 M os‘Atctg. f A“ , X 3 r .2. 5&0 ’ A. 0.25 M ‘* 5 3 a. 0.5: M ,. 3H" . r8. 0.050 M , J.» #4 er _ 0.33 M (jut LK'25- “at W " ' E. 0.60 M 4-- . ...
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This note was uploaded on 01/23/2011 for the course CHEM 3369 taught by Professor Roman during the Spring '09 term at University of Houston.

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Final_Fall07_Key - CI'SIOI 4 FINAL EXAM Fall 2007 CHEM 3369...

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