# enes_2 - pressure. This is seen in the function of power...

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C.J. Gorrell ENES 100 1. a. .5^2= .25m^2 p= 2(9.816)/.25= 78.528 n/m^2 V= Q/A p= density/2(Q/lhgap)^2 78.528 = 1.2/2(Q/(2*.002))^2 Q= .0457m^3/s P= pQ= 78.528(4.576E-2)= 3.593 W b. p .3m .5m .7m 1kg 109.067 39.264 20.0327 2kg 218 78.528 40.04 3kg 327 117.72 60.06 Q .3m .5m .7m 1kg .0323 .0323 .0323 2kg .0457 .0457 .0457 3kg .056 .056 .056 P .3m .5m .7m 1kg 3.52286 1.268 .647 2kg 9.96 3.593 1.8298 3kg 18.312 6.592 3.363 c. Based on my calculations, I have noticed that the flow rate of a hovercraft is dependent of mass, but not dependent of the area of the plenum. This is because for a given mass, if delta p increases when the perimeter decreases, causing Q to remain constant. For power consumption, I noticed that it is dependent of Flow rate and delta

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Unformatted text preview: pressure. This is seen in the function of power consumption where delta p and flow rate Picture 1 are direct variables. Ideally the best design would be to have a large plenum with the least possible mass. 2. The mentioned fan, would not fit the design of this circular hovercraft, because the performance point lies beyond that of the pressure vs air flow curve of this motor. Reasoning: p=1.5(9.81)/(pi(.67/2)^2)= 41.76 pa Q=(60*(2 p(lh)^2)/1.2)^.5=2.1m^3/min performance point 3 a. Q=1.2 p=13 pa V= Q/A= 1.2/60/(pi .046^2)= 3.01m/s T= pA= 13(pi.046^2)= .0864N pQ= 13*1.2/60 = .26 nm/s*.25= .065W...
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## This note was uploaded on 01/24/2011 for the course ENES enes100 taught by Professor Staff during the Spring '10 term at Maryland.

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enes_2 - pressure. This is seen in the function of power...

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