7 - Maximum: Normal stress = Mc/I = 18000(1.5)/6.1172 =...

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Centroid at midpoint of cross section Centroid, and Moment of Inertia Height = 3” flange width=3” flange thickness= ¾” web thickness = ¾” web height = 1.5” E= 7.5*10^5 Moment of Inertia = 1/12(3^4)-2(1/12(1.125*1.5^3)= 6.1172in.^4 Centroid = 1.5” from base
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Assuming weight of beam is negligible ∑Fy: Ry +Ly -1500= 0 ∑Mr: 1500(12) –Ry(20)=0 => Ry= 900 lb Ly= 600lb Moment max at 12” from left. = 1500lb*12in. = 18000 lb-in
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Unformatted text preview: Maximum: Normal stress = Mc/I = 18000(1.5)/6.1172 = 4413.78 psi = 4.413 ksi Shear stress: Vmax= 900lb Q= .75(3)(.75+.75/2) + .75(.75)(.75/2) = 2.742in.^3 B= .75in. =VQ/(IB) = 900(2.742)/[6.1172(.75)] = 537.89 psi max @ 12in. from left max @ horizontal through centroid, and at x less than 12in. Beam strength vs Material strength Sy= Sys= .577Syn...
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7 - Maximum: Normal stress = Mc/I = 18000(1.5)/6.1172 =...

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