Hw4stat - Christopher C.J Gorrell FEB 28th 2010 ENME392 6.9 avg=200 std=15 z=(224-200/15= 1.6 p(z>1.6 =.0548 6.12(a(b 6.14(a(b avg=99.61 std=.08

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
FEB. 28 th 2010 ENME392 6.9 avg=200 std=15 z= (224-200)/15= 1.6 p(z>1.6) = .0548 6.12 avg=99.61 std=.08 (a) p(99.5<x<99.7) = p(-1.375<z<1.125) = .7852 (b) .05 = P(z>1.645) 1.645*.08+99.61 = 99.74 6.14 n=1000 avg=174.5 std=6.9 (a) z=(160-174.5)/6.9 = -2.1 p(z<-2.1)= .0179*1000= 18 students (b) z=(171.25-174.5)/6.9 = -.047 z2=(182.25-174.5)/6.9 = 1.12 P(-.047<x<1.12)=.5494*1000 = 549 students (c) z=(174.75 -174.5)/6.9 = .04 z2=(175.25-174.5)/6.9=.11 P = .0278*1000= 28 students (d) z=(187.75-174.5)/6.9 =1.92 p=.0274 *1000 = 27 students 6.18 (a) x=avg + 1.3std x2=avg -1.3std 2p(z<-1.3) = 19.36% (b) p(-.52<x<.52)= 39.70% 6.23 n=15 p=.2 (a) .8358-.1671= .6687 (b) avg=np=3 std^2=npq=2.4 std=1.549 z=(.5-3)/1.549 =-1.61 z2=(4.5- 3)/1.549=.97 P(-1.61<x<.97)= .7803 6.28 avg=60 std= 3.873 n=80 p=.75 (a) z= (49.5-60)/3.873 = -2.71 P = .9966 (b) z=(56.5-60)/3.873 =-.9 p= .1841 6.34 avg= 30 std= 5 n= 180 p= 1/6 (a) z= (24.5-30)/5 =-1.1 P(z>-1.1)= .8643 (b) z= (32.5-30)/5 = .5 z2= (41.5-30)/5 =2.3 P(.5<z<2.3)= .2978
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/24/2011 for the course ENME enme392 taught by Professor Cukier during the Spring '10 term at Maryland.

Page1 / 4

Hw4stat - Christopher C.J Gorrell FEB 28th 2010 ENME392 6.9 avg=200 std=15 z=(224-200/15= 1.6 p(z>1.6 =.0548 6.12(a(b 6.14(a(b avg=99.61 std=.08

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online