chapter 9 slides

chapter 9 slides - Chemical Equilibria Chapter 9 CHEM 6B...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
1 Chemical Equilibria Chapter 9 CHEM 6B Dr. DiPasquale CHEMICAL PRINCIPLES: Chemical Equilibrium c The forward and reverse reactions are occurring simultaneously at the same rates. c There is no net change in the concentration of the products nor the reactants at chemical equilibrium. c How do we know if we are at chemical equilibrium? c Answer: change the conditions. c Does the equilibrium shift?
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
2 Chemical Equilibrium 2( ) 2 4( ) 2NO N O g s Chemical Equilibrium c All chemical equilibria are dynamic equilibria. c The composition of the reaction mixture can be expressed in terms of an equilibrium constant ( K ). c The equilibrium constant is characteristic of the reaction mixture at equilibrium at a given temperature.
Background image of page 2
3 Gas Equilibria equilibrium partial pressure of the products partial pressure of the reactants K = ( ) ( ) ( ) ( ) A B C D g g g g w x y z + + C D A B equilibrium y z w x P P K P P = Mixed Equilibria c Chemical equilibria with reactants and products that are all in the same phase are called homogeneous equilibria. c Chemical equilibria with reactants and products that are in more than one phase are called heterogeneous equilibria. c How do we deal with equilibria across different states?
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
4 Activity c For an ideal gas, it’s partial pressure ( P ) is equal to it’s activity ( a ). c For a solute in dilute solution, a = [X]. c For a pure solid or liquid, a = 1. A B C D w x y z + + C D A B equilibrium y z w x a a K a a = Example problem c Calculate the equilibrium constant at 25 °C for the following reaction: 4( ) 8( ) 2( ) 2 ( ) 2CH S 2CS 4H S g s l g + + 4 2 CH H S 0.8 atm, 0.6 atm P P = =
Background image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/25/2011 for the course CHEM 6BL taught by Professor Berniolles during the Spring '08 term at UCSD.

Page1 / 15

chapter 9 slides - Chemical Equilibria Chapter 9 CHEM 6B...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online