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Unformatted text preview: CS 341: Foundations of Computer Science II Prof. Marvin Nakayama Homework 5 Solutions 1. Give contextfree grammars that generate the following languages. (a) { w ∈ { , 1 } ∗  w contains at least three 1 s } Answer: G = ( V, Σ ,R,S ) with set of variables V = { S,X } , where S is the start variable; set of terminals Σ = { , 1 } ; and rules S → X 1 X 1 X 1 X X → X  1 X  ε (b) { w ∈ { , 1 } ∗  w = w R and  w  is even } Answer: G = ( V, Σ ,R,S ) with set of variables V = { S } , where S is the start variable; set of terminals Σ = { , 1 } ; and rules S → S  1 S 1  ε (c) { w ∈ { , 1 } ∗  the length of w is odd and the middle symbol is } Answer: G = ( V, Σ ,R,S ) with set of variables V = { S } , where S is the start variable; set of terminals Σ = { , 1 } ; and rules S → S  S 1  1 S  1 S 1  (d) { a i b j c k  i, j,k ≥ , and i = j or i = k } Answer: G = ( V, Σ ,R,S ) with set of variables V = { S,W,X,Y,Z } , where S is the start variable; set of terminals Σ = { a,b, c } ; and rules S → XY  W X → aXb  ε Y → cY  ε W → aWc  Z Z → bZ  ε 1 (e) { a i b j c k  i, j,k ≥ and i + j = k } Answer: G = ( V, Σ ,R,S ) with set of variables V = { S,X } , where S is the start variable; set of terminals Σ = { a,b,c } ; and rules S → aSc  X X → bXc  ε (f) ∅ Answer: G = ( V, Σ ,R,S ) with set of variables V = { S } , where S is the start variable; set of terminals Σ = { , 1 } ; and rules S → S Note that if we start a derivation, it never finishes, i.e., S ⇒ S ⇒ S ⇒ ··· , so no string is ever produced. Thus, L ( G ) = ∅ . (g) The language A of strings of properly balanced left and right brackets: ev ery left bracket can be paired with a unique subsequent right bracket, and every right bracket can be paired with a unique preceding left bracket. More over, the string between any such pair has the same property. For example, [[]] ∈ A . Answer: G = ( V, Σ ,R,S ) with set of variables V = { S } , where S is the start variable; set of terminals Σ = { [ , ] } ; and rules S → ε  SS  [ S ] 2. Let T = { , 1 , ( , ) , ∪ , ∗ , ∅ , e } . We may think of T as the set of symbols used by regular expressions over the alphabet { , 1 } ; the only difference is that we use e for symbol ε , to avoid potential confusion in what follows....
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This note was uploaded on 01/22/2011 for the course CIS 341 taught by Professor Nakayama during the Fall '10 term at NJIT.
 Fall '10
 Nakayama

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