Elements to Molecules

# Elements to Molecules - Elements to Molecules Elements •...

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Unformatted text preview: Elements to Molecules Elements • Sugar C6H12O6 • How much carbon, hydrogen, and How oxygen? oxygen? Elements to Molecules Elements • Sugar C6H12O6 • How much carbon, hydrogen, and How oxygen? oxygen? • 1 mol C6H12O6 • • • Carbon Carbon Hydrogen Oxygen _____ mol _____ _____ mol _____ mol Elements to Molecules Elements • Sugar C6H12O6 • How much carbon, hydrogen, and How oxygen? oxygen? • 1 mol C6H12O6 • • • Carbon Carbon Hydrogen Oxygen __6__ mol __ _____ mol _____ mol Elements to Molecules Elements • Sugar C6H12O6 • How much carbon, hydrogen, and How oxygen? oxygen? • 1 mol C6H12O6 • • • Carbon Carbon Hydrogen Oxygen __6__ mol __6__ __12_ mol _____ mol Elements to Molecules Elements • Sugar C6H12O6 • How much carbon, hydrogen, and How oxygen? oxygen? • 1 mol C6H12O6 • • • Carbon Carbon Hydrogen Oxygen __6__ mol __6__ __12_ mol __6__ mol Percent by Mass Percent • Multiply element’s molar mass by its Multiply subscript subscript • Divide by the compound’s molar mass • Multiply by 100 (subscript #)(element's molar mass) % of element = x 100 compounds molar mass Percent by Mass Example #1 Percent • Bicarbonate of soda (sodium hydrogen Bicarbonate carbonate) is used in many commercial preparations. Its formula is NaHCO3. preparations. • Find the mass percentages (mass %) of Find Na, H, C, and O in sodium hydrogen carbonate. carbonate. Percent by Mass Example #1 Percent • NaHCO3. • Find the mass percentages (mass %) of Find Na, H, C, and O in sodium hydrogen carbonate. carbonate. • Steps to solving: – Look up molar mass of each element – mol to mass – Calc molar mass of compound – Calc mass percentages of elements Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – Look up molar mass of each element – Na 22.99 g/mol Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – Look up molar mass of each element – Na 22.99 g/mol –H 1.008 g/mol Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – Look up molar mass of each element – Na 22.99 g/mol –H 1.008 g/mol –C 12.01 g/mol Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – Look up molar mass of each element – Na 22.99 g/mol –H 1.008 g/mol –C 12.01 g/mol –O 16.00 g/mol 16.00 Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – mol to mass – Na 22.99 g/mol 22.99 g Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – mol to mass – Na 22.99 g/mol –H 1.008 g/mol 22.99 g 1.008 g Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – mol to mass – Na 22.99 g/mol –H 1.008 g/mol –C 12.01 g/mol 22.99 g 1.008 g 12.01 g Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – mol to mass – Na 22.99 g/mol –H 1.008 g/mol –C 12.01 g/mol –O 3(16.00) g/mol 22.99 g 1.008 g 12.01 g 48.00 g Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – Calc molar mass of compound 22.99 g + 1.008 g + 12.01g + 48.00 g = 84.01g Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – Calc mass percentages of elements – Na 22.99 g/84.01 g x 100 = 27.36% Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – Calc mass percentages of elements – Na 22.99 g/84.01 g x 100 = 27.36% –H 1.008 g/84.01 g x 100 = 1.20% Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – Calc mass percentages of elements – Na 22.99 g/84.01 g x 100 = 27.36% –H 1.008 g/84.01 g x 100 = 1.20% –C 12.01 g/84.01 g x 100 = 14.30% Percent by Mass Example #1 Percent • NaHCO3. • Steps to solving: – Calc mass percentages of elements – Na 22.99 g/84.01 g x 100 = 27.36% –H 1.008 g/84.01 g x 100 = 1.20% –C 12.01 g/84.01 g x 100 = 14.30% –O 48.00 g/84.01 g x 100 = 57.14% Self Learning Self • Click here to view a video on mole, molar Click here mass, and percent mass mass, • Click here for a tutorial on percent by Click here mass mass • Click here for a practice quiz Click here ...
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## This note was uploaded on 01/28/2011 for the course CHM 101 taught by Professor Kershisnick during the Summer '10 term at Oakton.

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